Question

daca axb=45,iar cxa=35,calculeaza respectand ordinea efectarii operatiilor:
a) ax(b+c)+60=
b)ax(b-c)x3=
Daca axb=36,iar cxa=12,calculeaza:
c)ax(b+c)+72=
d)ax(b-c)-6=

Answer 1

• Datele problemei:

a*b=45

a*c=35

Rezolvare:

a) a*(b+c)+60=140

a*b+a*c+60=140

45+35+60=140

b) a*(b-c)*3=30

(a*b-a*c)*3=30

(45-35)*3=30

10*3=30

• Datele problemei:

a*b=36

a*c=12

Rezolvare:

c) a*(b+c)+72=120

a*b+a*c+72=120

36+12+72=120

d) a*(b-c)-6=18

a*b-a*c-6=18

36-12-6=18