Question

Daca c:d=3 rest 3, c+d=75 , a este 2/3 din c, iar b este impatritul treimii lui d, diferenta dintre suma numerelor a,b,d si numarul c este ?

Answer 1

Răspuns:

c:d=3 rest 3=>c=3d+3=>c=3·24+3=>c=72+3=>c=75

c+d=75=>3d+3=75=>3d=75-3=>d=72:3=>d=24

a=2c/3=>a=[2(3d+3)]/3=>a=(6d+6)/3=>a=(6·24+6)/3=>a=150/3=>a=50

b=4d/3=>b=(4·24)/3=>b=96/3=>b=32

(a+b+d)-c=(50+32+24)-75=106-75=31

Answer 2

Explicație pas cu pas:

c=3d+3 ; c+d=75;a=2c/3;b=4d/3; 3d+d+3=75 ;4d=75-3; 4d=72;d=72:4;d=18;b=4d/3=4•18/3=72/3=24;c=3•18+3=54+3=57; a=2•57/3=114:3=38; a+b+d-c=18+24+38-57=23