Question

Daca din suma a patru numere consecutive impare se ia 171,se obtine 245.care sunte cele 4 nr?

Answer 1

(a+b+c+d)-171=245
b=a+2
c=a+4
d=a+6

(a+b+c+d)-171=245
(a+a+2+a+4+a+6)-171=245
(4a+12)-171=245
4a+12-171=245
4a=245-12+171
4a=404 |:4
a=101
b=a+2=101+2=103
c=a+4=101+4=105
d=a+6=101+6=107

Coroana?

Answer 2

a;b;c;d=>nr.impare consecutive
a+b+c+d-171=245
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a=?b=?c=?d=?

a+b+c+d=245-171
a+b+c+d=416

a+a+2+a+4+a+6=416
4a+12=416
4a=416-12
4a=404
a=404:4
a=101
b=101+2
b=103
c=101+4
c=105
d=101+6
d=107

101+103+105+107-171=
=204+212-171
=416-171
=245