Question

Daca E(x) =2x ³-3x+6,atunci E (√2)= ?
Ajutor,dragii mei <3
Dau COROANA <3
P.s. Multumescc!!!

Answer 1

$E(x) =2x^3-3x+6 \\ \\ E(\sqrt2) = 2\cdot (\sqrt2)^3-3\sqrt2+6 \\ \\ E(\sqrt2) = 2\cdot \Big((\sqrt2)^2\cdot \sqrt2\Big)-3\sqrt2+6 \\ \\ E(\sqrt2) = 2\cdot 2\sqrt2 - 3\sqrt2+6 \\ \\ E(\sqrt2) = 4\sqrt2-3\sqrt2+6 \\ \\ E(\sqrt2) = \sqrt2+6$

Answer 2

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