Question

daca in triunghiul dr abc, AB/AC= 3/4, iar BC = 50 cm, aflati lungimea inaltimii corespunzatoare ipotenuzei

Answer 1

$\frac{AB}{AC}= \frac{3}{4} \Rightarrow AB=3k~ si~AC=4k. \\ \\ AB^2+AC^2=BC^2 \\ \\ 9k^2+16k^2=2500 \\ \\ 25k^2=2500 \\ \\ k^2=100 \\ \\ k=10. \\ \\ AB=3k=3 \cdot 10 =30~(cm). \\ \\ AC=4k=4 \cdot 10 =40~(cm).$

$h_a= \frac{AB \cdot AC}{BC}= \frac{30 \cdot 40}{50}= 24~(cm).$