Question

Dacă m (A)=32°13'26" ; m (B)=12°27'41" si m (C)=49°30'22" , calculati: m (A)+m (B)+m (C) ; m (B)+m (C)-m (A) ; 2 × [m (A)-m (B)+m (C).

Answer 1

1 grad =60 minute
1 minut=60 secunde
a)m(A)+m(B) +m(C)=
adunam secundele: 26+41+22=89 secunde =1minut si 29 secunde
adunam minutele: 13+27+30=70 minute =1 grad si 10 minute
adunam intai gradele :32+12+49=93 grade
grade=93+1=94
minute =10(cele ramase)+1=11 minut
secunde =29 (cele ramase dupa transformare)
total =94 grade 11minute si 29 secunde

b) m(B)+m(C)-m(A)=
12grade 27min 41sec+49grade 30 min 22 sec=
41 sec+22sec=63 sec=1min si 3 sec
27 min+30 min=57 min  (la care adunam minutul de mai sus)
12grade +49 grade=61 grade
total 61 grade 58 min si 3 sec
Apoi facem scaderea:61grade 58 min3sec-32grade13min26sec=
29grade44min37 sec

c)32*13'26"-12*27'41"=19*45'45"
19*45'45"+49*30'22"=69*16'07"
2x69*16'07"=138*32'14"

Answer 2

ai in imagine.........