Question

Daca ma poate ajuta si pe mine cineva e foarte urgent..
mulțumesc!​

Answer 1

$\it 7)\ \ a_3=10,\ a_6=22\\ \\ a_6=a_3+3r \Rightarrow r=\dfrac{a_6-a_3}{3}=\dfrac{22-10}{3}=\dfrac{12}{3}=4\\ \\ \\ a_{11}=a_3+8r=10+8\cdot4=42$

$\it 8)\ a_5=13,\ \ r=3\\ \\ a_{2011}=a_5+2006r=13+2006\cdot3=13+6018=6031$