Question

Daca maresc de 3ori varsta fiului si de 3 ori varsta mamei obtin nr 132 .Cati ani are fiecare daca diferenta dintre varstele lor este dw 5 ori mai mica decat nr 140. Metoda grafica

Answer 1

cu drag aici ai raspunsul

Answer 2

  
 3*m+3*f=132
  f=(132-m ):6                    m=(|___|___|___|*(140:5)+132-m) -132:3            
m=(3*(140:5)+132-m)-132-m:3                    f =(132-|___|___|___|):6
-------------------          ---------------------------------------------
m>f cu 140:5                     m=(3*(140:5)+132-m)-132-m:3
m-f=28                               f=(132-m):6


m=(3*(140:5)+132-m)-132-m:3
m-((3*(140/5)+132-m)-132-m/3=0
m-(((((140/5)+132)-m)-132)-m/3=0
m-(((((3*28)+132)-m)-132)-m/3)=0
84-m=8-m/1=(84m)*3 totul/3
(84-m)*3-(m)totul/3=252-4m totul/3
m-(252-4m) totul/3=252-4m /3
m-(252-4m)/3=0
m=m/1=m*3/3
254-4m=-4*(m-63) 
m*3-(-4*(m-63))totul/3=7m-252totul/3
7m*(m-36)totul/3=0
7*(m-36)totul/3 *3=0*3
7*(m-36)=0
7=0
m-36=0
m=36ani (are acum mama)

f=132-3*(140:5):6
f-((132-3*(140:5)):=0
f-(132-(3*28)) totul supra 6=0
f-8=0
f=8ani (are acum fiul)

3*m+3*f=132
36*3+8*3=136
108+24=36
m-f=140:5
36-8=28
28=28

sau

3m+3f=132                 |___|___|___|*m+|___|___|___|*f=132
m-f=140:5

3m+3f=132
m-f=28
m=28+f=>3m+3f=132
3*(28+f)+3f=132
84+3f=132
6f=132-84
6f=48
f=48:6
f=8 ani are fiul

3*m+3*8=132
3m=132-24
m=108
108:3=36
m=36 ani are mama

m-f=28
36-8=28

8*3=24
36*3=108

m+f=132
108+24=132