Question

Daca numarul complex z este o solutie a ecuatiei z²+2z+4=0 atunci Iz+1l este

Answer 1

Δ=-12
$z_{1}= \frac{-2-2 i\sqrt{3} }{2}=-1-i \sqrt{3} \\ z_{2}=-1+i \sqrt{3}$
IZ+1I=I-1+i√3+1I=Ii√3I=√3