Question

Daca numerele x,y,z sunt invers proportionale cu numerele 2,3, respectiv 6, si 2x-3y+4z=12, determina numerele x,y,z.

Answer 1

x/1/2=y/1/3=z/1/6=k
x=k/2
y=k/3
z=k/6
2x-3y+4z=12
2*k/2-3*k/3+4*k/6=12
2k/2-3k/3+4k/6=12  (amplificam fiecare numitor cu 6)
6k-6k+4k=72
4k=72
k=72/4=18
x=18/2=9
y=18/3=6
z=18/6=3