Question

Daca numerele x,y,z sunt invers proportionale cu numerele 2,3,6 si 2x-3y+4z=12 determina numerele x,y,z

Answer 1

x*2=y*3=z*6=k
2x-3y+4z=12
x=k/2
y=k/3
z=k/6
2*k/2-3*k/3+4*k/6=12
k-k+2k/3=12
2k/3=12
2k=36
k=18
x=18/2=9
y=18/3=6
z=18/6=3