Question

Daca numerele x, y, z sunt invers proportionale cu numerele 2; 3,respectiv 6 si 2x-3y+4z=12, determina numerele. 

Answer 1

x;y;z  ip cu 2,3,6

2x=3y=6z=k

x=k/2
y=k/3
z=k/6

2x-3y+4z=12

2* k/2 -3 * k/3 + 4*k/6=12

k -k + 2k/3=12

2k/3=12

k=3*12/2

k=3*6

k=18

x=18/2=9
y=18/3=6
z=18/6=3