Question

daca puteti sa-mi rezolvati testul va rog dau coroana si 10 pct

Answer 1

1.a)12-x=-3
-x=-3-12
-x=-15
x=15
b)x/3=1/4
x=3/4
c)√2x+√2-x=2-√2
√2x-x=2-√2-√2
x(√2-1)=2-2√2
x(√2-1)=2(1-√2)
x(√2-1)=(-2)(√2-1)
x=-2

2.Se,aduce,la,numitor,comun(6)
2(x-3)²-3(1-x)(1+x)=(5x-1)(x+2)-18
2(x²-6x+9)-3(1-x²)=5x²+9x-20
2x²-12x+18-3+3x²=5x²+9x-20
5x²-12x+15=5x²+9x-20
-12x+15-9x+20=0
-21x+35=0
-21x=-35l:-7
3x=5
x=5/3

3.√(7-4√3)=√(7-√48)=√[7+(√49-48)]/2-√[7-(√49-48)]/2
√(7+1)/2-√(7-1)/2=√4-√3=2-√3

√12=2√3

''Asamblam'',exercitiul:)
2√3-x(2-√3)=3
2√3-2x+√3x=3
x(√3-2)=3-2√3
x=(3-2√3)/(√3-2)

Cam,atat...mai,am,si,treaba,de,facut;)