Question

daca raportul a foua perimetre de patrate este 36/40 afla raportul ariilor acestora​

Answer 1

Răspuns:

$\frac{A_1}{A_2} =\frac{81}{100}$

Explicație pas cu pas:

$\frac{P_1}{P_2} =\frac{36}{40}$

$P_{patrat}=4l$

⇒$\frac{P_1}{P_2} =\frac{4l}{4l} =\frac{36}{40}$

⇒$\frac{l}{l} =\frac{36}{40} |:4=\frac{9}{10}$

$A_{patrat}=l^2$

⇒$\frac{A_1}{A_2} =\frac{l^2}{l^2} =(\frac{9}{10} )^2=\frac{81}{100}$

Answer 2

$\it Fie\ \ \ell_1,\ \ell_2\ laturile\ celor\ dou\breve a\ \ p\breve atrate$

$\it\ \dfrac{\mathcal{A}_1}{\mathcal{A}_2}=\dfrac{\ell^2_1}{\ell^2_2}= \Big(\dfrac{^{4)}\ell_1}{\ \ell_2}\Big)^2=\Big( \dfrac{4\ell_1}{4\ell_2}\Big)^2=\Big( \dfrac{\mathcal{P}_1}{\mathcal{P}_2}\Big)^2= \Big(\dfrac{\ 36^{(4}}{40}\Big)^2=\Big( \dfrac{9}{10}\Big)^2= \dfrac{81}{100}$