Question

Daca s-ar putea pe foaie sau pe caiet

Answer 1

Răspuns:

Explicație pas cu pas:

$\Big(\frac{ {}^{ \sqrt{2}) } 3}{ \sqrt{2} } - \frac{5 \sqrt{2} }{4}\Big) - \Big( \frac{\not{18} \sqrt{2} }{\not6} + \frac{ \not{12}}{\not3 \sqrt{2} }\Big)$

$= \frac{ {}^{2)} 3 \sqrt{2} }{2} - \frac{5 \sqrt{2} }{4} - \Big(3 \sqrt{2} + \frac{ {}^{ \sqrt{2}) } 4}{ \sqrt{2} } \Big)$

$= \frac{6 \sqrt{2} }{4} - \frac{5 \sqrt{2} }{4} - \Big(3 \sqrt{2} + \frac{\not4 \sqrt{2} }{\not2} \Big)$

$= \frac{ \sqrt{2} }{4} - (3 \sqrt{2} + 2 \sqrt{2} )$

$= \frac{ \sqrt{2} }{4} - {}^{4)} 5\sqrt{2} = \frac{\sqrt{2}}{4}- \frac{20\sqrt{2}}{4} = \boxed{- \frac{19 \sqrt{2}}{4}}$