Question

Daca $\frac{3}{5}$ ,calculati : a) $\frac{a}{2a+b}$
b) $\frac{a+b}{b}$
c)$\frac{2a+b}{a+3b}$


Va rog !!!! e urgent !!!

Answer 1

Banuiesc ca[tex]\frac{a}{b}=\frac{3}{5}, 5a=3b(1)\\ ^{5)}\frac{a}{2a+b}=}\frac{5a}{2\cdot 5a+5\cdot b}=\frac{3b}{6b+5b}=\frac{3b}{11b}=\frac{3}{11}.\\ \frac{a+b}{b}=^{5)}\frac{a+b}{b}=\frac{5a+5b}{5b}=\frac{3b+5b}{5b}=\frac{8b}{5b}=\frac{8}{5}.\\ \frac{2a+b}{a+3b}=^{5)}\frac{2a+b}{a+3b}=\frac{2\cdot5a+5b}{5a+3\cdot5b}=\frac{2\cdot 3b+5b}{3b+15b}=\frac{11b}{18b}=\frac{11}{18}[/tex]