Question

Daca $\frac{x}{13}$ = $\frac{y}{17}$, aflati: $\frac{x}{y}$; $\frac{y}{x}$; $\frac{3x}{y}$; $\frac{-2y}{x}$; $\frac{4y}{3x}$.

Answer 1

$\frac{x}{13} = \frac{y}{17} =>17x=13y=>x= \frac{13y}{17}$

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[tex] \frac{x}{y} = \frac{ \frac{13y}{17} }{y} =\frac{13y}{17}* \frac{1}{y} = \frac{13}{17} [/tex]

$\frac{y}{x} = (\frac{x}{y})^{-1} = (\frac{13}{17} )^{-1}= \frac{17}{13}$

[tex] \frac{3x}{y} =3* \frac{x}{y} =3* \frac{13}{17} = \frac{39}{17} [/tex]

$\frac{-2y}{x} =-2* \frac{y}{x} =-2* \frac{17}{13} = -\frac{34}{13}$

$\frac{4y}{3x} = \frac{4}{3} * \frac{y}{x} = \frac{4}{3} * \frac{17}{13} = \frac{68}{39}$