Question

Daca un copil isi numara timbrele cate 36 72 sau 168 de fiecare data raman 32 timbre in plus .cate timbre are daca numarul este cel mai mic cu aceasta proprietate

Answer 1

n:36 =c1 r 32, n=36c1+32
n:72=c2 r 32, n=72c2+32
n:168=c3 r 32, n=168c3+32

n-32=36c1=72c2=168 c3
n-32 e c.m.m.m.c al nr 36, 72 si 168
descompun nr in factori primi
36=2^2^3^2
72=2^3*3^2
168=2^3*3*7
[36,72,168]=2^3*3^2*7=504
n-32=504, n=504+32=536