Question

daca x+1\x=2,calculati x^2+1\x^2;x^3+1\x^3;x^4+1\x^4;x-1\x​

Answer 1

Explicație pas cu pas:

$(x + 1) \div x = 2 \\ x + 1 = 2 \times x \\ x = 1 \\ \\( x {}^{2} + 1) \div x {}^{2} = (1 {}^{2} + 1) \div 1 {}^{2} = 2 \div 1 = 2$

$(x {}^{3} + 1) \div x {}^{3} = 2$

$(x {}^{4} + 1) \div x {}^{4} = 2$

$(x - 1) \div x = (1 - 1) \div 1 = 0$