Question

daca x/2=y/3=z/4=t/5 si 4y + 2t =132 afla numerele x,y,z,t..

Answer 1

x/2=y/3=z/4=t/5 si 4y + 2t =132

y/3=t/5⇒y=(2/3)·t
4y + 2t =132⇒4(2t/3)+2t=132
12t+10t=132·5
22t=660
t=30

y=(2/3)·t=(2/3)·30
y=18

x/2=y/3⇒x=(2/3)·y=(2/3)·18⇒x=12
x=12

z/4=t/5
z=(4/5)·t=(4/5)·30
z=24


30.......100
12........x
x=1200:30
x=40%

Answer 2

x/2=y/3=z/4=t/5=k
x=2k
y=3k
z=4k
t=5k
12k+10k=132
22k=132 =>k=6
=>x=12, y=18, z=24 si t=30