Question

daca x+2y=17 si y-3z=4 atunci calculati
x+3y-3x
2x+5y-3z
(3x+6y)+(2y-6z)
(2x+4y)x(x+4y-6z)

Answer 1

•x +3y -3z = x + 2y + y - 3z = 17+4= 21
•2x +5y -3z = 2x +4y +y -3z = 2( x +2y) + y -3z = 2× 17 +4 = 34 +4= 38
•(3x +6y) + (2y - 6z) = 3(x + 2y) + 2( y-3z ) = 3×17 + 2× 4 = 51 + 8 = 59
• (2x + 4y)× (x + 4y -6z) = 2( x+ 2y) × [x + 2y + 2(y - 3z) ] = 2× 17 + ( 17 + 2× 4) = 34 + 25 = 59
sper ca te am ajutat :))