Question

daca x+2y=17 si y-3z=4
rapede va rog​
a)x+3y-3z=
b)2x+5y-3z=
c)(3x+6y)+(2y-6z)=

Answer 1

Răspuns:

Explicație pas cu pas:

x+2y=17 si y-3z=4

a) x+3y-3z= x + 2y + y - 3z = 17 + 4 = 21

b) 2x+5y-3z = 2x + 4y + y - 3z = 2(x+2y) + y-3z = 2·17+4 = 38

c) (3x+6y)+(2y-6z)= 3(x+2y) + 2(x-3z) = 3·17 + 2·4 = 59