Question

dacă x este numărul din egalitatea:5×53-{4×[5+(x-2)×7]:3}×6=1 .sa se determine valoarea lui x+1997.

Answer 1

5×53-{4×[5+(x-2)×7]:3}×6=1
265-{4×[5+(x-2)×7]:3}×6=1
{4×[5+(x-2)×7]:3}×6=264
4×[5+(x-2)×7]:3= 44
[5+(x-2)×7]:3=11
5+(x-2)×7=33
(x-2)×7=28
x-2=4
x=6
x+1997=2003

Answer 2

5×53-{4×[5+(x-2)×7]:3}×6=1
265-{4×[5+(x-2)×7]:3}×6=1
{4×[5+(x-2)×7]:3}×6=264
4×[5+(x-2)×7]:3= 44
[5+(x-2)×7]:3=11
5+(x-2)×7=33
(x-2)×7=28
x-2=4
x=6

6+1997=2003