Question

Daca :x + y =162, y + z =354, x+ z =408, afla valorile pentru x,y,z.

Answer 1

$x+y=162 \\ y+z=354 \\ x+z=408 \\ x+y+y+z+x+z=162+354+408 \\ 2x+2y+2z=924 \\ 2*(x+y+z)=924 \\ x+y+z=\frac{924}{2} \\ x+y+z=462 \\ 162+z=462 \\ z=462-162 \\ z=300 \\ 300+y=354 \\ y=354-300 \\ y=54 \\ 300+x=408 \\ x=408-300 \\ x=108$