Question

Daca x / y = 3/4 sa se afle valoarea raportului 7x-5y/8x+6y

Answer 1

$\frac{x}{y} = \frac{3}{4} =\ \textgreater \ x= \frac{3y}{4}$
$\frac{7x-5y}{8x+6y} = \frac{7 \frac{3y}{4} -5y}{8 \frac{3y}{4} +6y} = \frac{21y-20y}{24y+24y} = \frac{y}{48y} = \frac{1}{48}$