Question

Daca x - y = 3 si x^2(patrat) - y^2 = 12 , determinati numarul a=(x+y)+(x+y)^2+(x+y)^3

Answer 1

x-y=3;x^2-y^2=12=>(x-y)(x+y)=12=>3(x+y)=12=>x+y=12÷3=>x+y=4; a=(x+y)+(x+y)^2+(x+y)^3 <=> a=4+4^2+4^3=4+16+64=84;a=84.