Question

daca x-y =3 ; x^2-y^2=12 , determinati nr a= (x+y) + (x+y)^2 + (x+y)^3

Answer 1

x-y=3
x²-y²=12
(x-y)(x+y)=12
3(x+y)=12
x+y=4
Asadar :(x+y)²=16
              (x+y)³=64
a=x+y+(x+y)²+(x+y)³
a=4+16+64
a=20+64
a=84