Question

daca x\y = 4\5, atunxi 5x-3y\x+y

Answer 1

Răspuns:

$\frac{x}{y} =\frac{4}{5}= > x=\frac{4y}{5} \\\\\frac{5x-3y}{x+y} =\frac{5*\frac{4y}{5} -3y}{\frac{4y}{5}+ y} =\frac{\frac{20y-15y}{5} }{\frac{9y}{5} } =\frac{5y}{5} *\frac{5}{9y} =\frac{5y}{9y} =\frac{5}{9}$