Question

daca x+y/x-y =3/2 si x-y=16 , aflati x+3y

Answer 1

x+y/x-y=3/2 => x+y / 16 = 3/2 => x+y = 3*16/2 = 3*8=24
x=16+y => 16+y+y = 24 => 16+2y=24 => 2y=24-16 = 8 => y=8:2 = 4 => x=16+4 = 20 => x+3y = 20+3*4 = 20+12=32

Answer 2

(x + y)/(x-y)=3/2

⇒( x + y )/ 16 = 3/2 ⇒( x+y) = (3×16)/2 = 24

x - y = 16⇒x = 16 + y ⇒ 16 + y + y = 24

⇒ 16 + 2y = 24 ⇒ 2y = 24 - 16 ⇒2y = 8

⇒ y = 8:2 = 4 ⇒ x = 16 + y= 16 + 4 = 20

y = 4 si x = 20

x + 3y = 20+3×4 = 20+12 = 32⇒ x + 3y = 32