Question

Daca x+y+z=17 calculati 5.x+5.y+5.z= 13.x+13.y+13.z-1313= 882-3.(7.x+7.x+7.z)=

Answer 1

$x+y+z=17 \\ a).5y+5x+5z=5(x+y+z)=5 \cdot 17=85 \\ b).13x+13y+13z-1313=13(x+y+z)-1313= \\ =13 \cdot 17-1313=221-1313=-1092 \\ c).882-3(7x+7y+7z)=882-3[7(x+y+z)]= \\ =882-3 (7 \cdot 17)=882-3 \cdot 119=882-357=525$

Answer 2

x+y+z=17
5x+5y+5z= 5(x+y+z)=5*17=85 (il dai factor comun pe 5)
13x+13y+13z-1313=13(x+y+z)-1313=13*17-1313=221-1313=-1092 etc (sper ca te-ai prins)