Question

Daca xy=3 , yz=6 si xz=4 , calculati $x^{2} y^{2}z^{2}$

Answer 1

y=6/z
z=4/z
inlocuim in xy=3
6/z·(4/z)=3
24/z²=3
24=3z²
z²=24/3
z²=8
z=√8=2√2
z=2√2

x=6/z=6/2√2=3/√2=3√2/2
x=3√2/2

y=4/z=4/2√2=2/√2=2√2/2=√2
y=√2
x²y²z²=(3√2/2)²·(√2)²·(2√2)²=18/8·2/1·8/1=36
x²y²z²=36