Question

Dati factor comun in urmatoarele expresii:
1)6•a-18•b=
2)3•a+18•b-12•c=

Daca x+y+z=17 ,calculati
1)5•x+5•y+5•z=
2)13•x+13•y+13•z-1313=
3)882-3•(7•x+7•y+7•z)=
Sunt doua exercitii va rog ajutatima!!!
Ofer 15 pt

Answer 1

$1a).6a-18b=6(a-3b) \\ b).3a+18b-12c=3(a+6b-4c) \\ 2).x+y+z=17 \\ a).5x+5y+5z=5(x+y+z)=5 \cdot 17=85 \\ b).13x+13y+13z-1313=13(x+y+z)-1313= \\ =13 \cdot 17-1313=221-1313=-1092 \\ c).882-3(7x+7y+7z)=882-3[7(x+y+z)]= \\ =882-3(7 \cdot 17)=882-3 \cdot 119=882-357=525$