Question

dau 40 de puncte +coronita​

Answer 1

Explicație pas cu pas:

Sper să întregi

Aștept 40de puncte și coroana

Answer 2

$\it a)\ 2\sqrt3=\sqrt{2^2\cdot3}=\sqrt{4\cdot3}=\sqrt{12}\\ \\ \\ b)\ 5\sqrt{1,4}=\sqrt{5^2\cdot1,4}=\sqrt{25\cdot1,4}=\sqrt{35}\\ \\ \\ c)\ \dfrac{1}{3}\sqrt{24}=\sqrt{\Big(\dfrac{1}{3}\Big)^2\cdot24}=\sqrt{\dfrac{1}{9}\cdot24}=\sqrt{\dfrac{\ 24^{(3}}{9}}=\sqrt{\dfrac{8}{3}}$

$\it d)\ \ -3\sqrt2=-\sqrt{3^2\cdot2}=-\sqrt{9\cdot2}=-\sqrt{18}\\ \\ \\ e)\ \ -\dfrac{2}{3}\sqrt{15} =-\sqrt{\Big(\dfrac{2}{3}\Big)^2\cdot15}=-\sqrt{\dfrac{4}{9}\cdot15}=-\sqrt{\dfrac{\ 60^{(3}}{9}}=-\sqrt{\dfrac{20}{3}}\\ \\ \\ f)\ \  -\dfrac{5}{7}\sqrt{\dfrac{7}{5}}=-\sqrt{\Big(\dfrac{5}{7}\Big)^2\cdot\dfrac{7}{5}}=-\sqrt{\dfrac{5}{7}\cdot\dfrac{5}{7}\cdot\dfrac{7}{5}} =-\sqrt{\dfrac{5}{7}}$