Question

Dau 54 de puncte+coroana!!!
Ajutati-ma va rog frumos.....
1) Se considera rombul MNPQ avand aria egala cu 8√6 cm². Daca MP = 4√6 cm , aflati perimetrul MNPQ

Answer 1

$A=8\sqrt6 \ cm^2 \\ MP=4\sqrt6 \ cm \\ P-?} \\ P=4l \\ MN=NP=PQ=QM=l \\ A= \frac{d_1 \cdot d_2}{2} = \frac{MP \cdot NQ}{2} \\ d_2 \cdot 4\sqrt6 \ cm=2A=2 \cdot 8\sqrt6 \ cm^2=16\sqrt6 \ cm^2 \\ d_2= \frac{16\sqrt6 \ cm^2}{4 \sqrt6 \ cm^}}=\frac{16 \ cm^2}{4 \ cm} \\ d_2=4 \ cm \\ l^2=d_1^2+d_2^2=(4\sqrt6 \ cm)^2+(4 \ cm)^2 \\ l^2=\sqrt{96}^2+16 \ cm^2=96 \ cm^2+16 \ cm^2 \\ l^2=112 \ cm^2 \\ l=\sqrt{112} \ cm \\ l=4\sqrt7 \ cm \\ P=4l=4 \cdot 4 \sqrt7 \ cm \\ \Rightarrow \boxed{P=16 \sqrt7 \ cm}$

Answer 2

Perimetrul rombului MNPQ = ...................