Question

DAU caroana si 20 BALURI! ​

Answer 1

12.

A) (7/8-1/8)+1/4 =

= 6/8+1/4 =

6/8+1/4 care se amplifica cu 2; =

= 6/8+2/8 = 8/8 = 1


B) (5/6+7/6)-1/7 = 12/6-1/7 = 12/6 care se simplifica cu 7, iar 1:7 care se simplifica cu 6;= 84/42-6/42 = 78/42 simplificat cu 2 = 39/21 simplificat cu 3 = 13/7


C) (7/3-4/3)-12/13 = 3/3-12/13 = 1-12/13 = 1 amplificat cu 13 = 13/13-12/13 = 1/13


D) 4/3-(9/11+2/11) = 4/3-11/11 = 4/3-1 care se amplifica cu 3 = 4/3-3-3 = 1/3


13 nush cum sa-l fac...


Sper ca te-am ajutat! Bafta in continuare!

Answer 2

Răspuns:

12.a)

$( \frac{7}{8} - \frac{1}{8} ) + \frac{1}{4} = \\ = \frac{6}{8} + \frac{2}{8} = \\ = \frac{8}{8} = 1$

b)

$( \frac{5}{6} + \frac{7}{6}) - \frac{1}{7} = \\ = \frac{12}{6} - \frac{1}{7} = \\ = \frac{84}{42} - \frac{6}{42} = \\ = \frac{78}{42} = \frac{13}{7}$

c)

$( \frac{7}{3} - \frac{4}{3} ) - \frac{12}{13} = \\ = \frac{3}{3} - \frac{12}{13} = \\ = \frac{1}{13}$

d)

$\frac{4}{3} - ( \frac{9}{11} + \frac{2}{11} ) = \\ = \frac{4}{3} - \frac{11}{11} = \\ = \frac{1}{3}$

13.a)

$6 \frac{2}{7} - 4 \frac{1}{7} = \\ = \frac{6 \times 7 + 2}{7} - \frac{7 \times 4 + 1}{7} = \\ = \frac{44}{7} - \frac{29}{7} = \\ = \frac{15}{7}$

b)

$12 \frac{1}{9} - 5 \frac{4}{9} = \\ = \frac{119}{9} - \frac{49}{9} = \\ = \frac{70}{9}$

c)

$8 \frac{4}{5} - 3 \frac{1}{5} = \\ = \frac{44}{5} - \frac{16}{5} = \\ = \frac{28}{5}$

d)

$18 \frac{2}{11} - 7 \frac{5}{11} = \\ = \frac{200}{11} - \frac{82}{11} = \\ = \frac{118}{11}$