Question

DAU CORINITA:media geometrica a numerelor:a=(rad5-1)(1+rad10)
b=(rad10-1)(1+rad5)

Answer 1

$m_{g}(a,b)= \sqrt{ab}= \sqrt{( \sqrt{5}-1)(1+ \sqrt{10})( \sqrt{10}-1)(1+ \sqrt{5} ) }= \\ = \sqrt{[( \sqrt{5}-1)( \sqrt{5}+1)][( \sqrt{10}+1)( \sqrt{10}-1)] } = \\ = \sqrt{(5-1)(10-1)} = \\ = \sqrt{4*9} = \\ =2*3= \\ =6.$