Question

DAU COROANA!!!
1. Hidrocarburi izomere (inclusiv stereoizomeri) nu NE=0 si 84% C sunt in numar de....

2. Alchene izomere (onclusov stereoizomeri) C6H12 care la oxidare cu K2Cr2O7/H2SO4 respecta raportul molar C6H12: K2Cr2O7=3:4 sunt in numar de ....

Answer 1

CaHb      (2a+2-b)/2 = 0            b = 2a + 2       M = 14a + 2 
12a·100/(14a+2) = 84    100a= 7(14a + 2)     2a = 14     a = 7    C7H16 
CH3-(CH2)5-CH3;  CH3-CH(CH3)-CH2-CH2-CH2-CH3; 
CH3-CH2-C*H(CH3)-CH2-CH2-CH3 (2enantiomeri); 
CH3-(CH3)C(CH3)-CH2-CH2-CH3;  CH3-CH2-(CH3)C(CH3)-CH2-CH3;
CH3-(CH3)CH-(CH3)C*H-CH2-CH3; CH3-CH(CH3)-CH2-CH(CH3)-CH3;
CH3-CH2-CH(C2H5)-CH2-CH3
2. K2Cr2O7 + 4H2SO4 = K2SO4 + Cr2(SO4)3 + 4H2O + 3[O] 
nC6H12/nK2Cr2O7 = 3/4 ⇒  C6H12 + 4[O] ⇒ R1-COOH + R2-COOH
izomeri : 2hexena; 3hexena ; 4metil2pentena