Question

DAU COROANA!!!!!!!!!!!

Answer 1

a). $\frac{ 6^{-10} }{ 81^{-2} * 32^{-2} } = \frac{(2*3) ^{-10} }{ (3^{4}) ^{-2} * (2^{5})^{-2} }$
= $\frac{ 2^{-10} * 3^{-10} }{ 3^{-8}* 2^{-10} } = 3^{-2}$
{81 = $3^{4}$ si 32 = $2^{5}$} 

d). $= \frac{ -3^{-4} * (3^{3})^{10} }{ (3^{4})^{9} * ( 3^{2})^{-6} } =$
= $\frac{ -3^{4}* 3^{30} }{ 3^{36} * 3^{-12} } = \frac{ -3^{-4} }{3^{-6}} = \frac{0.012346}{0.001372} = 9$