Question

DAU COROANA!
[(-2)^8×3]^6 ÷ (-2)^45 ÷9=​?

Answer 1

Răspuns:

(-2)³·3^4=648

Explicație pas cu pas:

folosimm formula (a^m)n=a^m·n

[(-2)^8·3]^6=(-2)^48·3^6

si mai folosim formula

a^m÷a^n=a^m-n

(-2)^48·3^6÷(-2)^45÷3^2=

=(-2)^3·3^4=

=(-8)·81=648

sper ca am fost de folos

Answer 2

[(-2)^8×3]^6 ÷ (-2)^45 ÷9=​?

$\it [(-2)^8\cdot3]^6 : (-2)^{45} :9 = (2^8\cdot3)^6 : (-2)^{45} :9 =(2^{48}\cdot3^6):(-2)^{45}:3^2 =\\ \\ =2^{48}:(-2)^{45}\cdot(3^6:3^2)=-2^3\cdot3^4 =-8\cdot81=-648$