Question

Dau coroana....................................................

Answer 1

Sper că te-am ajutat :)

Answer 2

a)5x(x+1)/10(x+1)=5x/10=x/2
b)(x-1)^2/(x-1)(x+1)=
(x-1)(x-1)/(x-1)(x+1)=(x-1)/(x+1)
c)(x-1)(x+1)/(x+1)(x+1)=(x-1)/(x+1)
d) (x-3)^2/(x-3)(x+3)=
(x-3)(x-3)/(x-3)(x+3)=(x-3)/(x+3)
e)11(x^4-1)/22(x^2+1)=
(x^4-1)/2(x^2+1)=
(x^2-1)(x^2+1)/2(x^2+1) =
(^2-1)/2
f)2x(x^2-4a^2)/a(x^2+4ax+4a^2) =2x(x-2a)(x+2a)/a(x+2a)^2=
2x(x-2a)(x+2a)/a(x+2a)(x+2a)= 2x(x-2a)/a(x+2a)
g)3x(x^2-9a^2)/ax(9x^2-54ax+81a^2)=
3x(x-3a)(x+3a)/9ax(x^2-6ax+9a^2)=
3x(x-3a)(x+3a)/9ax(x-3a)^2=
(x-3a)(x+3a)/3a(x-3a)(x-3a)=
(x+3a)/3a(x-3a)=(x+3a)/(3ax-9a^2)