Question

dau coroană!!!!!!!!!​

Answer 1

Răspuns:

6. A= $\frac{3*5*7*2}{5*2*3 *7}$  = 1    se simplifica 3,2,5,7 de la numarator cu cele de la numitor

B= - $\frac{6}{7*5}$ * $\frac{5*7*6*2}{3*6}$ = $\frac{-12}{3}$ = -4

C= $\frac{3*7}{11}$ *(- $\frac{4}{5}$) *(- $\frac{2*11}{2*21}$) * $\frac{5*3}{4}$= $\frac{2*3}{2}$= 3

7. 1,25= $\frac{125}{100} = \frac{5}{4}$

a) $\frac{5}{4} * \frac{8}{7}$= $\frac{10}{7}$        b) $\frac{5}{4}$ *(-$\frac{1}{5}$)= - $\frac{1}{4}$

c) -5a * $\frac{2}{b}$= $\frac{-5*2a}{b}$= $\frac{-5*2*5}{4}$ = - $\frac{25}{2}$

d) $-\frac{a*4}{5b}$ = -$\frac{4*5}{5*4}$ = -1