Question

dau coroana!!!!!!!!!!!!!!!​

Answer 1

Răspuns:

$- 5(x + 2) + 4(x + 3) > 0 \\ - 5x - 10 + 4x + 12 > 0 \\ - x + 2 > 0 \\ - x > - 2 \\ x < 2$

$- 4x + 10 \geqslant 0 \\ - 4x \geqslant 10 \\ - x \geqslant \frac{10}{4} \\ x \leqslant - \frac{5}{2}$

$8x - 16 < 0 \\ 8x < 16 \\ x < \frac{16}{8 } \\ x < 2$

$2x \leqslant 4 \\ x \leqslant \frac{4}{2} \\ x \leqslant 2$