Question

dau coroana!!!!!!!!!!!!!

Answer 1

A=[1,3] B = (2,5) C = (-inf, 2)

a) A∩B = (2,3]

AUB=[1,5)

A/B=multime vida

B/A=(3,5)

b) A∩C=[1,2)

AUC=(-inf, 3]

A/C = [2,3]

C/A=(-inf,1)

c) B∩C=multime vida

BUC=(-inf,5)

B/C=(2,5)

C/B=(-inf,2)