Question

Dau coroana!!!!!!!!!! ​

Answer 1

${3}^{12} \div {3}^{10} + ( {3 \times 5})^{10} \div {15}^{9} - {2011}^{0} \times {1}^{2011} = {3}^{12 - 10} + {15}^{10} \div {15}^{9} - 1 \times 1 = {3}^{2} + {15}^{10 - 9} - 1 = {3}^{2} + {15}^{1} - 1 = 9 + 15 - 1 = 24 - 1 = 23$