Question

DAU COROANA!!!!!!!!!!!​

Answer 1

Răspuns:

a) 2Fe +3Cl2 => 2FeCl3 reacție de combinare

b)

MFe =56g/mol

MFeCl3= 56+3×35,5=162,5g/mol

m=n×M= 6×162,5=975g FeCl3

2×56g...............2×162,5g

2Fe +3Cl2 => 2FeCl3

xg.........................975g

x=975×2×56/2×162,5=calculează

calculam numarul de moli

2moli..................2moli

2Fe +3Cl2 => 2FeCl3

ymoli...............6moli

y=6×2/2=6 moli Fe