Question

Dau coroana!!!!!!!!! ​

Answer 1

Răspuns:

Explicație pas cu pas:

a) (x+2)(2x-1)-x(x+3)+1=2x²-x+4x-2-x²-3x+1=2x²-x²-x+4x-3x-2+1=

x²+3x-3x-1=x²-1

b)E(x)=x/(x³+x²):[ (x+2)(2x-1)-x(x+3)+1]/(2x+2)(3x-3)

       =x/x(x²+x):(x²-1)/[2(x+1)3(x-1)]=1/(x²+x):(x²-1)/6(x+1)(x-1)=

1/(x²+x):(x²-1)/6(x²-1)=1/(x²+x):(1/6)=1/(x²+x)·(6/1)=6/x²+x=6/x(x+1)