Question

DAU COROANA!!!
a) √(1 - √2)²=?
b) (√50 - 5√2)²⁰⁰⁹ · | 1 - √3 | + 2√3 - √12 = ?

Answer 1

a)  $\sqrt{(1-\sqrt 2)^2}$ = |1 - √2| = √2 - 1

b)  (√50 - 5√2)²⁰⁰⁹ · | 1 - √3 | + 2√3 - √12  =

= (5√2 - 5√2)²⁰⁰⁹ · (√3 - 1) + 2√3 - 2√3 =

= 0²⁰⁰⁹  · (√3 - 1) + 2√3 - 2√3 =

= 0 · (√3 - 1) + 0 =

= 0 + 0 =

= 0

Answer 2

Răspuns:

a) rad((1-rad(2))^2) =

= | 1 - rad(2) | (1 < rad(2)) =

= rad(2)-1

b) ((rad(50) - 5rad(2))^2009 * |1 - rad(3)| + 2rad(3) - rad(12) =

= (5rad(2) - 5rad(2))^2009 * | 1 - rad(3) | + 2rad(3) - 2 rad(3)

5rad(2) se reduce, la fel ca 2rad(3)

Ramanem cu rezultatul 0 :)

P.S. M.am speriat cand am vazut ^2009 acolo :))