Question

DAU COROANA......ACUMAAAA....IMEDIAT

Answer 1

Salut,

Știm că:

(a + b)² = a² + 2·a·b + b² și că (a -- b)(a + b) = a² -- b².

$x^2=\left(\sqrt{\sqrt{10}-3}+\sqrt{\sqrt{10}+3}\right)^2=\\\\=\left(\sqrt{\sqrt{10}-3}\right)^2+2\sqrt{\sqrt{10}-3}\cdot\sqrt{\sqrt{10}+3}+\left(\sqrt{\sqrt{10}+3}\right)^2=\\\\=\sqrt{10}-3+2\sqrt{(\sqrt{10}-3)(\sqrt{10}+3)}+\sqrt{10}+3=\\\\=2\sqrt{10}+2\sqrt{\left(\sqrt{10}\right)^2-3^2}=2\sqrt{10}+2\sqrt{10-9}=2\sqrt{10}+2.$

Green eyes.