Question

DAU COROANA !Aflati numarul y e Q+ din egalitatile urmatoare :a) y+3 supra 4 = 5 supra 6 b) 8 supra y-3 = 5 supra 7 c) 3 supra 4 = 2y - 1 supra 8 . Va rog ajutati-ma

Answer 1

a) (y+3)/4= 5/6=> 6 (y+3) =4×5=> 3 (y+3) =2×5 => y+3= 10/3 => y=10/3-3=>y=(10-9)/3=>y=1/3
b) 8/(y+3)=5/7=> 7×8 =5 (y-3) => 56=5 (y-3)=> y-3= 56/5=> y= 56/5 +3 => y= (56+15)/5=> y=71/5
c)3/4=(2y-1)/8 => 3×8=4 (2y-1) => 3×2 = 2y-1 => 6+1= 2y => y= 7/2