Question

Dau coroana!!
Aflati numerele x,y,z care indeplinesc conditiile:
x+y suppra 13=y+z supra 10= z+x supra 7; iar x+y+z= 30 ​

Answer 1

Explicație pas cu pas:

(x+y)/13=(y+z)/10=(z+x)/7

x+y+z=30=>

x+y=30-z

y+z=30-x

z+x=30-y

(30-z)/13=(30-x)/10=(30-y)/7

(30-z)/13=(30-x)/10=>

13(30-x)=10(30-z)=>

390-13x=300-10z=>

90=13x-10z

(30-x)/10=(30-y)/7 =>

10(30-y)=7(30-x)=>

300-10y=210-7x =>

10y-7x=90

=> 13x-10z=10y-7x

=> 13x+7x=10y+10z

=>20x=10(y+z)

=>2x=10(30-x)

=>2x=30-x

=>3x=30

=>x=10

x=10=>10y-70=90=>10y=160=>y=16

x=10=>130-10z=90=>10z=40=>z=4

(x,y,z)€{(10,16,4)}

S€{(10,16,4)}